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PART 3

For our part II project, we choose the Hilsburg non alcoholic malt drink conture glass bottle.Thus, we have to convert the line of the bottle into several functions so we can calculate the cross section and the volume of the bottles. Below are the lines of the bottle converted into cartesian plan.

The reason we only includes half of the bottle body because it will be easier to calculate its volume using the integration. And to calculate the cross section area of the bottle, we just have to multiply by 2 to have the overall value of its cross section area.

So, we have to names all the lines as f(x)_1, f(x)_2, f(x)_3, f(x)_4 and f(x)_5.
And we have to find the value of each functions.The coordinates for each functions are stated below:

f(x)_1 : (23,3) ,(10.5,3)
f(x)_2 : (10.5, 3) , (9, 1.75)
f(x)_3 : (9, 1.75) , (1, 1.25)
f(x)_4 : (1, 0) , (1, 1.25)
f(x)_5 : (23, 0) , ( 23, 3)

And the value of the functions are :

f(x)_1 : y = 3 ; where ( 23 <= x <= 10.5 )
f(x)_2 : 12y = 14x – 27 ; where ( 10.5 <= x <= 9 )
f(x)_3 : 16y = x + 7 ; where ( 9 <= x <= 1 )
f(x)_4 : x = 1 ; where (0 <= y <= 1.25 )
f(x)_5 : x = 23 ; where ( 0 <= y <= 3 )

Thus, we can calculate the area under the graph using the information above.

A = 10.5 ʃ 23 f(x)_1 + 9 ʃ 10.5 f(x)_2 + 1 ʃ 9 f(x)_3
A = 10.5 ʃ 23 (3 dx) + 9 ʃ 10.5 (14x – 27 dx) + 1 ʃ 9 (x + 7 dx )
   = 10.5[3x]23 + 9[7x2 – 27x]10.5 + 1[x2/2 + 7x]9
   = (37.5) + (164.25) + (96)
A = 297.75

And because we have to multiply A by 2, so the area of cross section of the bottle are
Cross-section bottle,
   = A*2
   = 595.5 cm2
And to find the volume of the bottle, we use the volume revolution of integration

Vb = π 10.5 ʃ 23 [f(x)_1]2 + π 9 ʃ 10.5 [f(x)_2]2 + π 1 ʃ 9 [f(x)_3]2
Vb = π10.5 ʃ 23 (3 dx)2 + π9 ʃ 10.5 (14x – 27 dx)2 + π1 ʃ 9 (x + 7 dx )2
      = π10.5 ʃ 23 (9 dx) + π9 ʃ 10.5 (196x2 – 756x + 729 dx) + π1 ʃ 9 (x2 +14x +49 dx )
Vb = 19347.67 π cm3

PART 2

PART 2

We use the model of Hilsburg non-alcoholic drink bottle for our model.Based on the upper area we will use the area of the circle which is:

A= A=πr^2

By using differentiation we can differentiate it:

2πr

For the whole body of the bottle we will use the formula:

A=πr2h

By using differentiation we get:

A=2πrh

PART 1

1. What is the definition and classification of ‘multimedia’? Give an definition and examples to support your definition.

Multimedia is media and content that uses a combination of different content forms. Multimedia is a large field of information technology (IT). Multimedia can be displayed ,showed, recorded and accessed. Example of multimedia are text,audio,video,animation,3D and interactive content form such as photography and photojournalism.This are all multimedia tools that can be displayed,showed,recorded and can be access.

2. What is the relevancy of TR1323 to the ‘multimedia’? Give examples.

The relevancy of TR1323 to multimedia is very important for calculating volume in making audio. We will use the application of calculating volume when making audio. Calculus is also used to maintain multimedia smoothing. Other than that, when studying object based structure this TR1323 will be applied to calculate the object volume.